Unit 11 Quiz--Equilibrium Constants |

__Multiple Choice__ (Choose the best answer.)

- An equilibrium constant for a reaction varies with
concentration of reactants.

concentration of products.

presence of a catalyst.

temperature.

All of the above.

- The equilibrium constant ( K
_{eq}) for the reaction, 2 SO_{2}(g) + O_{2}(g) 2 SO_{3}(g), is:{ 2 [SO

_{2}] + [O_{2}] } / 2 [SO_{3}]{ [SO

_{2}]^{ 2}x [O_{2}] } / [SO_{3}]^{2}2 [SO

_{3}] / { 2 [SO_{2}] + [O_{2}] }[SO

_{3}]^{2}/ { [SO_{2}]^{ 2}x [O_{2}] }None of the above.

- What would be the value of the equilibrium constant for the expression, 2 A B + C, if [A], [B], and [C] are 2.0 M, 3.0 M, and 4.0 M respectively.
0.33

3.0

3.5

6.0

None of the above are correct.

The reaction, X Y has a K _{eq}= 3. If the reaction reaction starts out with 12 Xs, how many Xs and Ys will there be when equilibrium is reached? (See the picture at right.)12 X and 0 Y

9 X and 3 Y

3 X and 9 Y

12 X and 36 Y

None of these.

- Calcium hydroxide, Ca(OH)
_{2}, is only slightly soluble in water. The K_{sp}expression for Ca(OH)_{2}is:K

_{sp}= [Ca][OH]^{2}K

_{sp}= [Ca][2 x OH]K

_{sp}= [Ca^{2+}][2 x OH^{-}]K

_{sp}= [Ca^{2+}][OH^{-}]K

_{sp}= [Ca^{2+}][OH^{-}]^{2}

- The K
_{sp}of CaCO_{3}is 4.5 x 10^{-9}. What is the molar solubility of CaCO_{3}?6.7 x 10

^{-5}M2.3 x 10

^{-9}M4.5 x 10

^{-9}M2.0 x 10

^{-15}MNone of these are correct.

- The solubility of CaF
_{2}is 2.1 x 10^{-4}. Find the K_{sp}of CaF_{2}.4.4 x 10

^{-8}9.3 x 10

^{-12}3.7 x 10

^{-11}0.037

None of these are correct.

- Reactions tend to form the most products when
the disorder increases and the energy content increases.

the disorder increases and the energy content decreases.

the disorder decreases and the energy content increases.

the disorder decreases and the energy content decreases.

None of the above are correct.

- Which of the reactions below would you expect to largest equilibrium constant in terms of disorder and energy?
MgCO

_{3}(s) MgO (s) + CO_{2}(g); H = 13.9 KJ2 PbS (s) + 3 O

_{2}(g) 2 SO_{2}(g) + 2 PbO (s); H = - 835.0 KJC

_{2}H_{5}OH (l) C_{2}H_{5}OH (g); H = 43 KJC

_{2}H_{4}(g) + H_{2}(g) C_{2}H_{6}(g); H = -137 KJ4 HCN (l) + 5 O

_{2}(g) 4 CO_{2}(g) + 2 H_{2}O (g) + 2 N_{2}(g); H = - 2500 KJ

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