Unit 12 Quiz--Bronsted-Lowry Theroy and KA Values

Multiple Choice (Choose the best answer.)

  1. A Bronsted-Lowry acid is defined as a substance that

    accepts a proton

    accepts an electron

    donates a proton

    donates an electron

    none of the above


  2. While the Arrhenius and Bronsted-Lowry theories of acids are very similar, the two theories view bases quite differently. Which definitions of base behavior for the two theories are correct?
      Arrhenius Theory Bases Bronsted-Lowry Theory Bases
     Accept H+  Increase [OH-] in Solution
     Donate H+  Increase [OH-] in Solution
     Decrease [OH-] in Solution  Accept H+
     Decrease [OH-] in Solution  Donate H+
     None of these are correct.  

    The following reaction will be used in questions 3 - 5: HF + HCO3 - F - + H2CO3
  3. Identify the bases in the reaction.

    HF and HCO3 -

    F - and H2CO3

    HF and H2CO3

    F - and HCO3 -

    HF and F -


  4. If the KA for HF = 6.7 x 10 -4 and the KA for H2CO3 = 4.4 x 10 -7, which direction will the reaction favor?

    towards the products

    towards the reactants

    neither toward the reactants nor toward the products since an equilibrium is established

    It is impossible to say.

    None of the above are correct.


  5. Which of the following is an acid - base pair in the reaction?

    HF and HCO3 -

    F - and H2CO3

    HF and H2CO3

    F - and HCO3 -

    HF and F -


  6. HNO2 ionizes according to the reaction: HNO2 H+ + NO2 -. If the [H+ ] of a 0.20 M solution of HNO2 is 0.010 M, what is the KA?

    0.010

    0.05

    5.0 x 10 -4

    2.0 x 10 3

    None of the above are correct.


  7. If HSO3 - has a KA of 6.2 x 10 -8 , what will be the [H+ ] of a 0.10 M solution of HSO3 -?

    6.2 x 10 -9 M

    6.2 x 10 -8 M

    7.9 x 10 -5 M

    0.10 M

    None of the above are correct.


  8. Benzoic acid ionizes according to the reaction: C6H5COOH H + + C6H5COO -. What would be the effect on the concentration of C6H5COO - if some OH - was added to the equilibrium?

    [ C6H5COO - ] would increase

    [ C6H5COO - ] would decrease

    [ C6H5COO - ] remain the same

    It is impossible to predict any effect.

    None of the above are correct.


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